var myPost = function(url,args,ajax_form_options){    var body = $(document.body),form = $("
    
"),input;    form.attr({"action":url});    for(var key in args){    	input = $("");        input.attr({"name":key});        input.val(args[key]);        form.append(input);    }    form.appendTo(document.body);    form.ajaxSubmit(ajax_form_options);    document.body.removeChild(form[0]);}var ajax_form_options = {	success : function(data) {		//成功的回调函数	}}		var url = '/xxx/xxx/xxx';var param = {'xxx' : xxx};myPost(url,param,ajax_form_options);需要引入jquery-1.7.2.min.js和jquery-form.js